20250108

1960.两个回文子字符串长度的最大乘积.java

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+/*
+ * @lc app=leetcode.cn id=1960 lang=java
+ *
+ * [1960] 两个回文子字符串长度的最大乘积
+ */
+
+// @lc code=start
+
+import java.util.ArrayList;
+import java.util.List;
+
+class Solution {
+    public long maxProduct(String s) {
+        List<Integer> stringAsciiList = conv2ascii(s);
+        List<Integer> stringAndList = new ArrayList<>();
+        int listLength = stringAsciiList.size();
+        for (int i = 0; i < listLength; i++) {
+            int a = stringAsciiList.get(i) + stringAsciiList.get(listLength - 1 - i);
+            int b = stringAsciiList.get(i) * 2;
+            stringAndList.add(a == b ? 1 : 0);
+        }
+        System.out.println(stringAndList);
+
+        return 0;
+
+    }
+
+    /**
+     * 获取字符串的ascii码字符串
+     * 
+     * @param s
+     * @return
+     */
+    private List<Integer> conv2ascii(String s) {
+        List<Integer> stringAsciiList = new ArrayList<>();
+        for (char item : s.toCharArray()) {
+            stringAsciiList.add((int) item);
+        };
+        return stringAsciiList;
+
+    }
+
+    public static void main(String[] args) {
+        Solution solution = new Solution();
+        solution.maxProduct("ababbb");
+    }
+
+}
+// @lc code=end